CS401 Assignment 1 solution 2020 with Download file and code

CS401 ASSIGNEMENT SOLUTION 2020

 Q 1. Calculate the effective address for the following set of values. (5)

Code Segment = 6032h

BX = 3060h

DI = 4001h

Offset = 0470h

Solution:

CS = 5032h

BX = 3060h

DI = 4001h

Offset = 0470h

Effective Address = ?

Here memory access under consideration is [CS:BX+DI+Offset]

Then the Effective address = BX+DI+Offset

= 3060h + 4001h + 0470h

Efffecctive Address = 74D1h

Q 2. Find the physical Address, if segment address is FF01H and offset is FF02H. (7)

Segment Address = FF01h

Offset Address = FF02h

Physical Address = ?

Physical Address = (Segment Address * 10) + Offset Address

= (FF01h * 10) + FF02h

= FF010h + FF02h

Physical Address = 10EF12h

Q 3. Calculate the offset when the physical address is 003Ch and the contents of segment register are 003Ah. (8)

Physical Address = 003Ch

Segment Register = 003Ah

Offset = ?

Physical Address = Segment Register + Offset Address

Offset = Physical Address - Segment Register

Offset = 003Ch – 003Ah

Offset = 0002h