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CS302 Assignment 2 solution 2019

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CS302 Assignment 2 solution 2019
1.       Write  the SOP expression for the given  sum
∑ABCDE(2,4,6,8,10,12,14,16,18,20,22,24,26,28)

A
B
C
D
E
0
0
0
0
0
0
0
0
0
1
0
0
0
1
0
0
0
0
1
1
0
0
1
0
0
0
0
1
0
1
0
0
1
1
0
0
0
1
1
1
0
1
0
0
0
0
1
0
0
1
0
1
0
1
0
0
1
0
1
1
0
1
1
0
0
0
1
1
0
1
0
1
1
1
0
0
1
1
1
1
1
0
0
0
0
1
0
0
0
1
1
0
0
1
0
1
0
0
1
1
1
0
1
0
0
1
0
1
0
1
1
0
1
1
0
1
0
1
1
1
1
1
0
0
0
1
1
0
0
1
1
1
0
1
0
1
1
0
1
1
1
1
1
0
0
1
1
1
0
1
1
1
1
1
0
1
1
1
1
1








A
B
C
D
E
Decimal value
Output
(f)
0
0
0
0
0
0
0
0
0
0
0
1
1
0
0
0
0
1
0
2
1
0
0
0
1
1
3
0
0
0
1
0
0
4
1
0
0
1
0
1
5
0
0
0
1
1
0
6
1
0
0
1
1
1
7
0
0
1
0
0
0
8
1
0
1
0
0
1
9
0
0
1
0
1
0
10
1
0
1
0
1
1
11
0
0
1
1
0
0
12
1
0
1
1
0
1
13
0
0
1
1
1
0
14
1
0
1
1
1
1
15
0
1
0
0
0
0
16
1
1
0
0
0
1
17
0
1
0
0
1
0
18
1
1
0
0
1
1
19
0
1
0
1
0
0
20
1
1
0
1
0
1
21
0
1
0
1
1
0
22
1
1
0
1
1
1
23
0
1
1
0
0
0
24
1
1
1
0
0
1
25
0
1
1
0
1
0
26
1
1
1
0
1
1
27
0
1
1
1
0
0
28
1
1
1
1
0
1
29
0
1
1
1
1
0
30
1
1
1
1
1
1
31
0
















                          


Q2
ANS:
Find the prime implicant of minterm using Quine mcculsky method
∑ABCDE(2,4,6,8,10,12,14,16,18,20,22,24,26,28)
00010
2
00100
4
01000
8
10000
16
00110
6
01010
10
01100
12
10010
18
10100
20
11000
24
01110
14
10110
22
11010
26
11100
28
11110
30












Step 2:
2,6(00-10) 2,10(0-010) 2,18(-0010)
4,12(0-100)4,6(001-0)4,20(-0100)
8,10(010-0)8,24(-1000)
6,14(0-110)6,22(-0110)
10,14(01-10)10,26(-1010)
12,14(011-0)12,28(-1100)
18,26(1-010) 18,22(1-100)
20,22(101-0)20,22(1-100)
24,26(110,0)24,28(11-00)
14,30(-1110)22,30(1-110)26,30(11,10)28,30(111-0)


Step 3:
2,6,18,22(-0-10)    2,6,10,14(0--10)           2,10,18,26(--010)
2,18,6,22(-0-10)
2,18,10,26(--010)         4,12,6,14(0-1-0)           4,6,12,14(0-1-0)
4,6,20,22(-01-1)           4,20,6,22(-01-0)           4,20,12,28(--100)
8,10,12,14(01-0)          8,24,10,26(-10-0)         8,24,12,28(-1-00)
6,14,22,30(--110)         6,22,14,30(--110)         10,14,26,30(-1-10)
10,26,14,30(-1-10)      12,14,28,30(-11-0)      12,14,28,30(-11-0)
18,26,22,30(1—10)     18,22,26,30(1—10)     20,22,28,30(1-1-0)
20,22,22,30(1-1-0)      24,26,28,30(11-0)   24,28,26,30(11-0)

These are the prime implicant.

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2 comments:

  1. UML DocumentationNovember 25, 2019 at 11:13 AM

    This is not the complete solution

    ReplyDelete
  2. naeemullahNovember 26, 2019 at 12:19 AM

    file k under complete solution a .yaha adjust nhi horha tha screen pay.

    ReplyDelete

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